Answer

Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

Apne doubts clear karein ab Whatsapp par bhi. Try it now.

CLICK HERE

Watch 1000+ concepts & tricky questions explained!

13.8 K+

600+

Text Solution

`q=0,DeltaT lt0,w cancel(=) 0``q=0, DeltaTcancel(=) 0,w=0``qcancel(=) 0,DeltaT , w=0``q=0,DeltaT=0,w=0`

Answer :

DSolution :

For adiabatic expansion, `q=0` <br> For free expansion, `P_(ext) = 0`. Hence,`w-0` <br> `DeltaU = q+w=0+0=0`. As U is a function of temperature `( U = (3)/(2) nRT)` and as `DeltaU = 0, :.DeltaT =0`